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XX項(xiàng)目(一期)二期工程施工用電方案AAAA建設(shè)集團(tuán)有限公司XXXX FIRST CONSTRUCTION GROUP CO.,LTD.目 錄第一章 編制依據(jù)3第二章 工程概況3一、 總體工程概況3二、 施工場地基本概況4三、 電源接駁點(diǎn)概況4第三章 施工部署4一、 總體目標(biāo)4二、 現(xiàn)場臨時(shí)用電部署:三級(jí)配電二級(jí)保護(hù)4三、 組織機(jī)構(gòu)5四、 技術(shù)準(zhǔn)備7五、 勞動(dòng)力準(zhǔn)備8六、 機(jī)具準(zhǔn)備8七、 材料準(zhǔn)備9第四章 臨時(shí)用電布置說明9一、 參數(shù)設(shè)置10二、 臨電初步設(shè)計(jì)原則18第五章 臨時(shí)用電計(jì)算18一、 用電負(fù)荷計(jì)算18二、 導(dǎo)線及開關(guān)箱內(nèi)電氣設(shè)備選擇50三、 一級(jí)配電柜的進(jìn)線、開關(guān)箱內(nèi)電氣設(shè)備選擇80第六章 繪制臨時(shí)供電施工圖81一、 一級(jí)配電柜系統(tǒng)圖83二、 二級(jí)配電箱供電系統(tǒng)圖83第七章 安全用電技術(shù)措施86一、 安全用電技術(shù)措施86二、 安全用電組織措施99第八章 安全用電防火措施100一、 施工現(xiàn)場發(fā)生火災(zāi)的主要原因101二、 預(yù)防電氣火災(zāi)的措施102三、 防雷裝置設(shè)計(jì)104第九章 接地裝置設(shè)計(jì)104第十章 施工用電總承包管理105一、 管理流程106二、 管理要點(diǎn)106三、 施工現(xiàn)場臨時(shí)用資料管理108四、 停電事故預(yù)防措施110第十一章 應(yīng)急措施及救援預(yù)案111第十二章 施工用電總平面布置114第一章 編制依據(jù)序號(hào)名稱編號(hào)1建筑電氣工程施工施質(zhì)量驗(yàn)收規(guī)范GB50303-20152建筑施工現(xiàn)場供用電安全規(guī)范GB5019420143施工現(xiàn)場臨時(shí)用電安全技術(shù)規(guī)范JGJ4620054建筑施工安全檢查標(biāo)準(zhǔn)JGJ59-20115建筑施工現(xiàn)場臨時(shí)建筑物技術(shù)規(guī)范JGJ/T188-20096建筑工程施工現(xiàn)場消防安全技術(shù)規(guī)范GB50720-20117低壓配電設(shè)計(jì)規(guī)范GB50054-20118通用用電設(shè)備配電設(shè)計(jì)規(guī)范GB50055-20119供配電系統(tǒng)設(shè)計(jì)規(guī)范GB50052-200910環(huán)境與職業(yè)健康安全體系11本工程施工圖12本工程施工組織設(shè)計(jì)第二章 工程概況一、 總體工程概況工程名稱地理位置建設(shè)單位設(shè)計(jì)單位勘察單位監(jiān)理單位本項(xiàng)目為二期四棟雙層倉庫,其中,3號(hào)庫房22306.02m2, 4號(hào)庫房23455.28 m2 ,5號(hào)庫房23382.10 m2,6號(hào)庫房24066.46 m2,倉庫為錘擊樁、承臺(tái)基礎(chǔ),一、二層為框架結(jié)構(gòu),屋面及墻面等維護(hù)結(jié)構(gòu)為輕鋼結(jié)構(gòu)。局部區(qū)域設(shè)置有辦公及設(shè)備夾層。一層倉庫結(jié)構(gòu)層高為11.00m,二層倉庫結(jié)構(gòu)層高為10.00m。二、 施工場地基本概況為滿足施工進(jìn)度及運(yùn)輸要求,每一個(gè)庫準(zhǔn)備投入2臺(tái)QTZ6013塔吊,一共8臺(tái)塔吊。以及其他加工設(shè)備(見設(shè)備及功率明細(xì)表)?,F(xiàn)場布置8個(gè)鋼筋加工車間和2個(gè)木工加工車間,每2棟倉庫統(tǒng)一設(shè)置一個(gè)一級(jí)配電柜。三、 電源接駁點(diǎn)概況1 本工程電源接駁點(diǎn)分別位于場地南側(cè)七庫外側(cè)的800KVA的配電房,現(xiàn)場可提供本工程臨時(shí)用電量容量為800KVA。2 本工程按項(xiàng)目總的進(jìn)度計(jì)劃結(jié)合本方案第五章第一條第7點(diǎn)和第14點(diǎn)和17點(diǎn)計(jì)算結(jié)果,到最高峰時(shí)的用電量為497.58KVA,滿足施工需求。3 本工程采用三級(jí)配電,從總配電室到各一級(jí)配電柜,一級(jí)配電柜到各二級(jí)配電箱,各庫二及配電箱至各用電點(diǎn)三級(jí)開關(guān)箱。第三章 施工部署一、 總體目標(biāo)質(zhì)量目標(biāo):合格,一次驗(yàn)收合格率100%。安全目標(biāo):堅(jiān)持“安全第一、預(yù)防為主”的工作方針,確保無重大工傷事故,輕傷頻率控制在4以內(nèi)。二、 現(xiàn)場臨時(shí)用電部署:三級(jí)配電二級(jí)保護(hù)現(xiàn)場在變壓器旁設(shè)置總配電室各一級(jí)配電柜各棟分別設(shè)置3個(gè)二級(jí)配電箱各設(shè)備專用插座箱、照明專用箱為三級(jí)箱;本工程分期建設(shè):一期有1號(hào)、2號(hào)庫區(qū)及配套用房;二期有3號(hào)、4號(hào)、5號(hào)、6號(hào)四棟庫區(qū)及配套用房,本方案為二期施工用電方案。在3號(hào)庫、4號(hào)庫之間設(shè)置1#一級(jí)配電柜、5號(hào)庫、6號(hào)庫之間設(shè)置2#一級(jí)配電柜、辦公區(qū)和生活區(qū)設(shè)置專用3#一級(jí)配電柜。根據(jù)總進(jìn)度計(jì)劃安排,每棟庫房之間開始施工的時(shí)間順序相差十天;一套基礎(chǔ)錘擊樁所使用的設(shè)備需用70KW,按三套設(shè)備同時(shí)施工共有210KW,錘擊樁設(shè)備施工的時(shí)候,其他如鋼筋、模板加工設(shè)備還沒有投入使用,塔吊也沒有完全投入使用,并且三套錘擊樁的負(fù)荷小于基礎(chǔ)主體施工階段用電設(shè)備的負(fù)荷,所以在施工臨時(shí)用電負(fù)荷計(jì)算的時(shí)候,不考慮錘擊設(shè)備的用電負(fù)荷。主體施工階段及裝飾裝修期間用電高峰是塔吊、鋼筋加工、模板加工設(shè)備同時(shí)使用的階段,所以最大負(fù)荷主要考慮各樓層施工機(jī)具、照明、模板加工,塔吊運(yùn)轉(zhuǎn)及鋼筋加工的用電。擬從配電房設(shè)置一個(gè)主線路到總配電室;3號(hào)4號(hào)庫共用1#一級(jí)配電柜,5號(hào)6號(hào)庫共用2#一級(jí)配電柜、辦公區(qū)和生活區(qū)共用3#一級(jí)配電柜;各一級(jí)配電柜分別設(shè)置4條線路至固定二級(jí)配電箱(鋼筋加工場地配電箱和塔吊配電箱)和2條線路至各棟物流庫樓層的移動(dòng)二級(jí)配電箱(樓層用電配電箱)。從二級(jí)箱引出線至三級(jí)箱及專用設(shè)備控制箱,實(shí)現(xiàn)一機(jī)一閘一漏。三、 組織機(jī)構(gòu)1 項(xiàng)目成立項(xiàng)目施工用電總承包管理機(jī)構(gòu),管理機(jī)構(gòu)如下:圖略組長:副組長:組員:2 組長XX負(fù)責(zé)整個(gè)項(xiàng)目施工用電的方案審核、施工及管理工作;3 副組長項(xiàng)目技術(shù)負(fù)責(zé)人XX負(fù)責(zé)施工用電方案的編制及方案流程報(bào)審,各分包單位用電方案的審核,并對(duì)方案進(jìn)行交底和技術(shù)核定;4 各組員XX負(fù)責(zé)整個(gè)施工現(xiàn)場施工用電的施工、檢查及施工用電總承包管理;5 XX主要根據(jù)方案編制要求及現(xiàn)場實(shí)際情況對(duì)施工用電布置進(jìn)行指導(dǎo)及檢查,中期主要對(duì)項(xiàng)目設(shè)備施工用電進(jìn)行維護(hù)及管理,后期主要進(jìn)行施工用電總承包管理。6 XX負(fù)責(zé)施工用電材料的采購;XX負(fù)責(zé)施工用電的施工及管理;質(zhì)檢員負(fù)責(zé)對(duì)現(xiàn)場施工用電質(zhì)量進(jìn)行監(jiān)督管理并進(jìn)行相關(guān)報(bào)驗(yàn)工作安全總監(jiān)、安全員主要負(fù)責(zé)施工用電的安全管理;7 同時(shí)施工用電總承包管理機(jī)構(gòu)各成員均需對(duì)施工用電的安全進(jìn)行管理。四、 技術(shù)準(zhǔn)備1 組織各崗位管理人員學(xué)習(xí)有關(guān)法律、法規(guī)、規(guī)范、圖紙,經(jīng)考核合格后持證上崗,杜絕無證上崗現(xiàn)象。2 召開現(xiàn)場技術(shù)交底會(huì)議,就現(xiàn)場臨電工程施工技術(shù)要求對(duì)現(xiàn)場機(jī)管員、電工、操作工人進(jìn)行交底,使其施工前作好充分準(zhǔn)備。3 對(duì)勞務(wù)隊(duì)伍全體人員進(jìn)行進(jìn)場前安全文明施工教育及管理宣傳。4 對(duì)特殊工作作業(yè)人員去專業(yè)的機(jī)構(gòu)培訓(xùn),考核合格取證后方可上崗。5 施工作業(yè)人員入場教育(1) 施工用電作業(yè)人員先必須經(jīng)過項(xiàng)目安全員、主管工長、機(jī)管員、勞資員及保衛(wèi)組織的項(xiàng)目安全常識(shí)系統(tǒng)教育,并建立相應(yīng)的檔案資料。(2) 施工用電作業(yè)人員分配到工作面后,應(yīng)由項(xiàng)目機(jī)管員結(jié)合工程的具體情況及特點(diǎn)作專項(xiàng)技術(shù)交底。并形成相應(yīng)記錄。(3) 針對(duì)施工過程中階段性出現(xiàn)的具有的特定性的安全問題及隱患,機(jī)管員必須現(xiàn)場作針對(duì)性交底,并形成相關(guān)記錄。五、 勞動(dòng)力準(zhǔn)備據(jù)施工時(shí)間的劃分,選定一支勞務(wù)分包單位進(jìn)行施工用電施工,每支勞務(wù)隊(duì)伍必須配置專業(yè)電工且必須持證上崗。序號(hào)工種人數(shù)備注1管理人員102電工63普工12六、 機(jī)具準(zhǔn)備序號(hào)設(shè)備名稱單位數(shù)量備注1穿線器套1用于電纜管內(nèi)穿線2電工工具套6用于電纜的搭接3壓接鉗套1用于電纜頭壓接七、 材料準(zhǔn)備名稱單位數(shù)量型號(hào)備注總配電室個(gè)1變壓器開關(guān)柜出至項(xiàng)目總配電室的配電箱一級(jí)配電柜個(gè)3二期施工總配電箱固定二級(jí)配電柜個(gè)14為每個(gè)庫區(qū)和辦公生活區(qū)移動(dòng)三級(jí)配電箱及設(shè)備專用箱個(gè)4用于樓層配電,每棟配置一個(gè)每臺(tái)設(shè)備及生活區(qū)、辦公區(qū)每棟樓配置一個(gè)開關(guān)箱鋁芯絕緣電纜m1380mVLV3*150mm+2*70mm電纜鋁芯絕緣電纜m420mVLV3*70mm+2*35mm電纜鋁芯絕緣電纜m2220mVLV3*50mm+2*25mm電纜鋁芯絕緣電纜m800mVLV3*25mm+2*16mm電纜第四章 臨時(shí)用電布置說明 本施工現(xiàn)場臨時(shí)用電施工組織設(shè)計(jì)通過計(jì)算選擇合理導(dǎo)線截面積,電器設(shè)備及控制方式,既能滿足現(xiàn)場施工用電需要,又能保障現(xiàn)場安全用電的要求,做到節(jié)能、方便,規(guī)范、標(biāo)準(zhǔn)。 根據(jù)施工現(xiàn)場用電設(shè)施布置情況,從配電室至一級(jí)配電柜施工區(qū)域電纜采用穿管暗埋方式。電纜線從項(xiàng)目總配電室引入一級(jí)配電柜,由一級(jí)配電柜再分別設(shè)置回路至二級(jí)配電箱,由二級(jí)配電箱供至各機(jī)械設(shè)備開關(guān)箱等,應(yīng)當(dāng)配電合理,互不干擾防止因電氣故障影響施工。一級(jí)配電柜與二級(jí)配電箱之間電纜場地情況選擇穿管埋設(shè)方式。二級(jí)配電箱與用電設(shè)備之間電線選擇架空敷設(shè)。埋設(shè)和架空敷設(shè)方式和注意事項(xiàng)詳見本方案第七章相關(guān)要求。一、 參數(shù)設(shè)置1.一級(jí)配電柜參數(shù)(1)1#一級(jí)配電柜參數(shù)用電接駁方式由總配電室接入一級(jí)配電柜編號(hào)1#一級(jí)配電柜一級(jí)配電柜距接駁點(diǎn)布線距離Lo(m)20一級(jí)配電柜的同期使用系數(shù)Kx0.8分配電箱數(shù)量6導(dǎo)線線芯材料鋁線一級(jí)配電柜進(jìn)線敷設(shè)方式埋地暗敷二級(jí)配電箱進(jìn)線敷設(shè)方式埋地暗敷設(shè)備電線敷設(shè)方式埋地暗敷/架空線路干線允許電壓降%5(2)2#一級(jí)配電柜參數(shù)用電接駁方式由總配電室接入一級(jí)配電柜編號(hào)2#一級(jí)配電柜一級(jí)配電柜距接駁點(diǎn)布線距離Lo(m)20一級(jí)配電柜的同期使用系數(shù)Kx0.8分配電箱數(shù)量6導(dǎo)線線芯材料鋁線一級(jí)配電柜進(jìn)線敷設(shè)方式埋地暗敷二級(jí)配電箱進(jìn)線敷設(shè)方式埋地暗敷設(shè)備電線敷設(shè)方式埋地暗敷/架空線路干線允許電壓降%5(3)3#一級(jí)配電柜參數(shù)用電接駁方式由總配電室接入一級(jí)配電柜編號(hào)3#一級(jí)配電柜一級(jí)配電柜距接駁點(diǎn)布線距離Lo(m)20一級(jí)配電柜的同期使用系數(shù)Kx0.8分配電箱數(shù)量2導(dǎo)線線芯材料鋁線一級(jí)配電柜進(jìn)線敷設(shè)方式埋地暗敷二級(jí)配電箱進(jìn)線敷設(shè)方式埋地暗敷設(shè)備電線敷設(shè)方式埋地暗敷/架空線路干線允許電壓降%102.供電系統(tǒng)設(shè)置總箱編號(hào)干線名稱分配電箱編號(hào)安裝部位同期使用系數(shù)Kx(m)功率因素Cos分箱到一級(jí)配電箱布線距離1#一級(jí)配電柜1號(hào)干線3-1號(hào)二級(jí)配電箱3#物流庫塔吊0.70.7570m2號(hào)干線3-2號(hào)二級(jí)配電箱3#物流庫鋼筋、木工加工區(qū)0.70.75150m3號(hào)干線3-3號(hào)二級(jí)配電箱3#物流庫樓層0.70.75120m4號(hào)干線4-1號(hào)二級(jí)配電箱4#物流庫塔吊0.70.7570m5號(hào)干線4-2號(hào)二級(jí)配電箱4#物流庫鋼筋、木工加工區(qū)0.70.75150m6號(hào)干線4-3號(hào)二級(jí)配電箱4#物流庫樓層0.70.75120m2#一級(jí)配電柜7號(hào)干線5-1號(hào)二級(jí)配電箱5#物流庫塔吊0.70.7570m8號(hào)干線5-2號(hào)二級(jí)配電箱5#物流庫鋼筋、木工加工區(qū)0.70.75150m9號(hào)干線5-3號(hào)二級(jí)配電箱5#物流庫樓層0.70.75120m10號(hào)干線6-1號(hào)二級(jí)配電箱6#物流庫塔吊0.70.7570m11號(hào)干線6-2號(hào)二級(jí)配電箱6#物流庫鋼筋、木工加工區(qū)0.70.75150m12號(hào)干線6-3號(hào)二級(jí)配電箱6#物流庫樓層0.70.75120m3#一級(jí)配電柜13號(hào)干線7號(hào)二級(jí)配電箱辦公區(qū)14號(hào)干線8號(hào)二級(jí)配電箱生活區(qū)3.用電設(shè)備參數(shù)(1)1#一級(jí)配電柜用電設(shè)備參數(shù)(2)2#一級(jí)配電柜用電設(shè)備參數(shù)(3)3#一級(jí)配電柜用電設(shè)備參數(shù)4.臨電設(shè)備配置參數(shù)(1)1#一級(jí)配電柜各分箱用電設(shè)備配置參數(shù)(2)2#一級(jí)配電柜各分箱用電設(shè)備配置參數(shù)(3)3#一級(jí)配電柜各分箱用電設(shè)備配置參數(shù)二、 臨電初步設(shè)計(jì)原則1 施工現(xiàn)場臨時(shí)用電安全技術(shù)規(guī)范(JGJ46-2005)總則中以強(qiáng)制性條文規(guī)定,施工現(xiàn)場必須采用三級(jí)配電系統(tǒng)、必須采用TN-S接零保護(hù)系統(tǒng)。2 現(xiàn)場采用380V低壓供電,設(shè)一配電1#一級(jí)配電柜,采用TN-S系統(tǒng)供電。3 布置位置及線路走向參見臨時(shí)配電系統(tǒng)圖,采用三級(jí)配電,三級(jí)防護(hù)。4 按照J(rèn)GJ46-2005規(guī)定制定施工組織設(shè)計(jì),接地電阻R4。5 按照J(rèn)GJ46-2005規(guī)定若為架空線路則“根據(jù)機(jī)械強(qiáng)度要求,絕緣銅線截面不小于10mm2,絕緣鋁線截面不小于16mm2”。第五章 臨時(shí)用電計(jì)算一、 用電負(fù)荷計(jì)算1、3-1號(hào)二級(jí)配電箱設(shè)備用電負(fù)荷(1)1#塔式起重機(jī)Kx = 0.7,Cos = 0.65,tg = (1 - Cos2)0.5/ Cos = (1 - 0.652)0.5 / 0.65 = 1.17Pe = n P (e/)0.5 = 1.00 32.80 (0.40 / 0.25)0.5 = 41.49kWIj1 = Kx Pe / (1.732 Ue cos) = 0.70 41.49 1000 / (1.732 380 0.65) = 67.89APjs = Kx Pe = 0.70 41.49 = 29.04kWQjs = Pjs tg = 29.04 1.17 = 33.95kvA(2)2#塔式起重機(jī)Kx = 0.7,Cos = 0.65,tg = (1 - Cos2)0.5/ Cos = (1 - 0.652)0.5 / 0.65 = 1.17Pe = n P (e/)0.5 = 1.00 32.80 (0.40 / 0.25)0.5 = 41.49kWIj1 = Kx Pe / (1.732 Ue cos) = 0.70 41.49 1000 / (1.732 380 0.65) = 67.89APjs = Kx Pe = 0.70 41.49 = 29.04kWQjs = Pjs tg = 29.04 1.17 = 33.95kvA(3)LED泛光燈照明Kx = 0.6,Cos = 0.6,tg = (1 - Cos2)0.5/ Cos = (1 - 0.62)0.5 / 0.6 = 1.33Pe = n P (e/)0.5 = 2.00 0.40 (0.40 / 0.40)0.5 = 0.80kWIj1 = Kx Pe / (1.732 Ue cos) = 0.60 0.80 1000 / (1.732 380 0.60) = 1.22APjs = Kx Pe = 0.60 0.80 = 0.48kWQjs = Pjs tg = 0.48 1.33 = 0.64kvA(4)塔吊臂燈Kx = 0.6,Cos = 0.9,tg = (1 - Cos2)0.5/ Cos = (1 - 0.92)0.5 / 0.9 = 0.48Pe = n P (e/)0.5 = 8.00 1.00 (0.40 / 0.40)0.5 = 8.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.60 8.00 1000 / (1.732 380 0.90) = 8.10APjs = Kx Pe = 0.60 8.00 = 4.80kWQjs = Pjs tg = 4.80 0.48 = 2.32kvA(5)3-1號(hào)二級(jí)配電箱計(jì)算負(fù)荷用電設(shè)備同期使用系數(shù)Kx=0.70;Ijs = Kx Pe / (1.732 Ue Cos) = 0.70 91.78 1000 / (1.732 380 0.75) = 130.15A;同時(shí)要求分箱用電負(fù)荷不得小于分箱下用電設(shè)備最大計(jì)算負(fù)荷的1.1倍,故:Ijs = max130.15,1.1max(67.89,67.89,1.22,8.10,) = 130.15A2、3-2號(hào)二級(jí)配電箱設(shè)備用電負(fù)荷(1)鋼筋切斷機(jī)Kx = 0.2,Cos = 0.65,tg = (1 - Cos2)0.5/ Cos = (1 - 0.652)0.5 / 0.65 = 1.17Pe = n P (e/)0.5 = 1.00 2.20 (0.40 / 0.40)0.5 = 2.20kWIj1 = Kx Pe / (1.732 Ue cos) = 0.20 2.20 1000 / (1.732 380 0.65) = 1.03APjs = Kx Pe = 0.20 2.20 = 0.44kWQjs = Pjs tg = 0.44 1.17 = 0.51kvA(2)鋼筋彎曲機(jī)Kx = 0.65,Cos = 0.7,tg = (1 - Cos2)0.5/ Cos = (1 - 0.72)0.5 / 0.7 = 1.02Pe = n P (e/)0.5 = 2.00 3.00 (0.40 / 0.40)0.5 = 6.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.65 6.00 1000 / (1.732 380 0.70) = 8.47APjs = Kx Pe = 0.65 6.00 = 3.90kWQjs = Pjs tg = 3.90 1.02 = 3.98kvA(3)鋼筋套絲機(jī)Kx = 0.2,Cos = 0.65,tg = (1 - Cos2)0.5/ Cos = (1 - 0.652)0.5 / 0.65 = 1.17Pe = n P (e/)0.5 = 1.00 4.00 (0.40 / 0.40)0.5 = 4.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.20 4.00 1000 / (1.732 380 0.65) = 1.87APjs = Kx Pe = 0.20 4.00 = 0.80kWQjs = Pjs tg = 0.80 1.17 = 0.94kvA(4)鋼筋箍筋彎曲機(jī)Kx = 0.2,Cos = 0.65,tg = (1 - Cos2)0.5/ Cos = (1 - 0.652)0.5 / 0.65 = 1.17Pe = n P (e/)0.5 = 1.00 3.00 (0.40 / 0.40)0.5 = 3.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.20 3.00 1000 / (1.732 380 0.65) = 1.40APjs = Kx Pe = 0.20 3.00 = 0.60kWQjs = Pjs tg = 0.60 1.17 = 0.70kvA(5)數(shù)控鋼筋調(diào)直切斷機(jī)Kx = 0.2,Cos = 0.65,tg = (1 - Cos2)0.5/ Cos = (1 - 0.652)0.5 / 0.65 = 1.17Pe = n P (e/)0.5 = 1.00 3.00 (0.40 / 0.40)0.5 = 3.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.20 3.00 1000 / (1.732 380 0.65) = 1.40APjs = Kx Pe = 0.20 3.00 = 0.60kWQjs = Pjs tg = 0.60 1.17 = 0.70kvA(6)電動(dòng)切割機(jī)Kx = 0.3,Cos = 0.45,tg = (1 - Cos2)0.5/ Cos = (1 - 0.452)0.5 / 0.45 = 1.98Pe = n P (e/)0.5 = 1.00 1.80 (0.40 / 0.40)0.5 = 1.80kWIj1 = Kx Pe / (1.732 Ue cos) = 0.30 1.80 1000 / (1.732 380 0.45) = 1.82APjs = Kx Pe = 0.30 1.80 = 0.54kWQjs = Pjs tg = 0.54 1.98 = 1.07kvA(7)木工圓鋸Kx = 0.65,Cos = 0.6,tg = (1 - Cos2)0.5/ Cos = (1 - 0.62)0.5 / 0.6 = 1.33Pe = n P (e/)0.5 = 1.00 1.50 (0.40 / 0.40)0.5 = 1.50kWIj1 = Kx Pe / (1.732 Ue cos) = 0.65 1.50 1000 / (1.732 380 0.60) = 2.47APjs = Kx Pe = 0.65 1.50 = 0.98kWQjs = Pjs tg = 0.98 1.33 = 1.30kvA(8)木工平刨床Kx = 0.65,Cos = 0.6,tg = (1 - Cos2)0.5/ Cos = (1 - 0.62)0.5 / 0.6 = 1.33Pe = n P (e/)0.5 = 1.00 3.00 (0.40 / 0.40)0.5 = 3.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.65 3.00 1000 / (1.732 380 0.60) = 4.94APjs = Kx Pe = 0.65 3.00 = 1.95kWQjs = Pjs tg = 1.95 1.33 = 2.60kvA(9)LED泛光燈照明Kx = 0.3,Cos = 0.7,tg = (1 - Cos2)0.5/ Cos = (1 - 0.72)0.5 / 0.7 = 1.02Pe = n P (e/)0.5 = 1.00 0.30 (0.50 / 0.50)0.5 = 0.30kWIj1 = Kx Pe / (1.732 Ue cos) = 0.30 0.30 1000 / (1.732 380 0.70) = 0.20APjs = Kx Pe = 0.30 0.30 = 0.09kWQjs = Pjs tg = 0.09 1.02 = 0.09kvA(10)3-2號(hào)二級(jí)配電箱計(jì)算負(fù)荷用電設(shè)備同期使用系數(shù)Kx=0.70;Ijs = Kx Pe / (1.732 Ue Cos) = 0.70 24.80 1000 / (1.732 380 0.75) = 35.17A;同時(shí)要求分箱用電負(fù)荷不得小于分箱下用電設(shè)備最大計(jì)算負(fù)荷的1.1倍,故:Ijs = max35.17,1.1max(1.03,8.47,1.87,1.40,1.40,1.82,2.47,4.94,0.20,) = 35.17A3、3-3號(hào)二級(jí)配電箱設(shè)備用電負(fù)荷(1)插入式振動(dòng)器Kx = 0.3,Cos = 0.7,tg = (1 - Cos2)0.5/ Cos = (1 - 0.72)0.5 / 0.7 = 1.02Pe = n P (e/)0.5 = 4.00 1.10 (0.40 / 0.40)0.5 = 4.40kWIj1 = Kx Pe / (1.732 Ue cos) = 0.30 4.40 1000 / (1.732 380 0.70) = 2.87APjs = Kx Pe = 0.30 4.40 = 1.32kWQjs = Pjs tg = 1.32 1.02 = 1.35kvA(2)直流電焊機(jī)Kx = 0.3,Cos = 0.6,tg = (1 - Cos2)0.5/ Cos = (1 - 0.62)0.5 / 0.6 = 1.33Pe = n P (e/)0.5 = 4.00 10.00 (0.50 / 1.00)0.5 = 28.28kWIj1 = Kx Pe / (1.732 Ue cos) = 0.30 28.28 1000 / (1.732 380 0.60) = 21.49APjs = Kx Pe = 0.30 28.28 = 8.49kWQjs = Pjs tg = 8.49 1.33 = 11.31kvA(3)沖擊錘鉆Kx = 0.2,Cos = 0.7,tg = (1 - Cos2)0.5/ Cos = (1 - 0.72)0.5 / 0.7 = 1.02Pe = n P (e/)0.5 = 6.00 1.00 (0.40 / 0.40)0.5 = 6.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.20 6.00 1000 / (1.732 380 0.70) = 2.60APjs = Kx Pe = 0.20 6.00 = 1.20kWQjs = Pjs tg = 1.20 1.02 = 1.22kvA(4)樓層各種照明Kx = 0.3,Cos = 0.7,tg = (1 - Cos2)0.5/ Cos = (1 - 0.72)0.5 / 0.7 = 1.02Pe = n P (e/)0.5 = 1.00 10.00 (0.40 / 0.50)0.5 = 8.94kWIj1 = Kx Pe / (1.732 Ue cos) = 0.30 8.94 1000 / (1.732 380 0.70) = 5.82APjs = Kx Pe = 0.30 8.94 = 2.68kWQjs = Pjs tg = 2.68 1.02 = 2.74kvA(5)3-3號(hào)二級(jí)配電箱計(jì)算負(fù)荷用電設(shè)備同期使用系數(shù)Kx=0.70;Ijs = Kx Pe / (1.732 Ue Cos) = 0.70 47.63 1000 / (1.732 380 0.75) = 67.54A;同時(shí)要求分箱用電負(fù)荷不得小于分箱下用電設(shè)備最大計(jì)算負(fù)荷的1.1倍,故:Ijs = max67.54,1.1max(2.87,21.49,2.60,5.82,) = 67.54A4、4-1號(hào)二級(jí)配電箱設(shè)備用電負(fù)荷(1)3#塔式起重機(jī)Kx = 0.7,Cos = 0.65,tg = (1 - Cos2)0.5/ Cos = (1 - 0.652)0.5 / 0.65 = 1.17Pe = n P (e/)0.5 = 1.00 32.80 (0.40 / 0.25)0.5 = 41.49kWIj1 = Kx Pe / (1.732 Ue cos) = 0.70 41.49 1000 / (1.732 380 0.65) = 67.89APjs = Kx Pe = 0.70 41.49 = 29.04kWQjs = Pjs tg = 29.04 1.17 = 33.95kvA(2)4#塔式起重機(jī)Kx = 0.7,Cos = 0.65,tg = (1 - Cos2)0.5/ Cos = (1 - 0.652)0.5 / 0.65 = 1.17Pe = n P (e/)0.5 = 1.00 32.80 (0.40 / 0.25)0.5 = 41.49kWIj1 = Kx Pe / (1.732 Ue cos) = 0.70 41.49 1000 / (1.732 380 0.65) = 67.89APjs = Kx Pe = 0.70 41.49 = 29.04kWQjs = Pjs tg = 29.04 1.17 = 33.95kvA(3)LED泛光燈照明Kx = 0.6,Cos = 0.6,tg = (1 - Cos2)0.5/ Cos = (1 - 0.62)0.5 / 0.6 = 1.33Pe = n P (e/)0.5 = 2.00 0.40 (0.40 / 0.40)0.5 = 0.80kWIj1 = Kx Pe / (1.732 Ue cos) = 0.60 0.80 1000 / (1.732 380 0.60) = 1.22APjs = Kx Pe = 0.60 0.80 = 0.48kWQjs = Pjs tg = 0.48 1.33 = 0.64kvA(4)塔吊臂燈Kx = 0.6,Cos = 0.9,tg = (1 - Cos2)0.5/ Cos = (1 - 0.92)0.5 / 0.9 = 0.48Pe = n P (e/)0.5 = 8.00 1.00 (0.40 / 0.40)0.5 = 8.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.60 8.00 1000 / (1.732 380 0.90) = 8.10APjs = Kx Pe = 0.60 8.00 = 4.80kWQjs = Pjs tg = 4.80 0.48 = 2.32kvA(5)4-1號(hào)二級(jí)配電箱計(jì)算負(fù)荷用電設(shè)備同期使用系數(shù)Kx=0.70;Ijs = Kx Pe / (1.732 Ue Cos) = 0.70 91.78 1000 / (1.732 380 0.75) = 130.15A;同時(shí)要求分箱用電負(fù)荷不得小于分箱下用電設(shè)備最大計(jì)算負(fù)荷的1.1倍,故:Ijs = max130.15,1.1max(67.89,67.89,1.22,8.10,) = 130.15A5、4-2號(hào)二級(jí)配電箱設(shè)備用電負(fù)荷(1)鋼筋切斷機(jī)Kx = 0.2,Cos = 0.65,tg = (1 - Cos2)0.5/ Cos = (1 - 0.652)0.5 / 0.65 = 1.17Pe = n P (e/)0.5 = 1.00 2.20 (0.40 / 0.40)0.5 = 2.20kWIj1 = Kx Pe / (1.732 Ue cos) = 0.20 2.20 1000 / (1.732 380 0.65) = 1.03APjs = Kx Pe = 0.20 2.20 = 0.44kWQjs = Pjs tg = 0.44 1.17 = 0.51kvA(2)鋼筋彎曲機(jī)Kx = 0.65,Cos = 0.7,tg = (1 - Cos2)0.5/ Cos = (1 - 0.72)0.5 / 0.7 = 1.02Pe = n P (e/)0.5 = 2.00 3.00 (0.40 / 0.40)0.5 = 6.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.65 6.00 1000 / (1.732 380 0.70) = 8.47APjs = Kx Pe = 0.65 6.00 = 3.90kWQjs = Pjs tg = 3.90 1.02 = 3.98kvA(3)鋼筋套絲機(jī)Kx = 0.2,Cos = 0.65,tg = (1 - Cos2)0.5/ Cos = (1 - 0.652)0.5 / 0.65 = 1.17Pe = n P (e/)0.5 = 1.00 4.00 (0.40 / 0.40)0.5 = 4.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.20 4.00 1000 / (1.732 380 0.65) = 1.87APjs = Kx Pe = 0.20 4.00 = 0.80kWQjs = Pjs tg = 0.80 1.17 = 0.94kvA(4)鋼筋箍筋彎曲機(jī)Kx = 0.2,Cos = 0.65,tg = (1 - Cos2)0.5/ Cos = (1 - 0.652)0.5 / 0.65 = 1.17Pe = n P (e/)0.5 = 1.00 3.00 (0.40 / 0.40)0.5 = 3.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.20 3.00 1000 / (1.732 380 0.65) = 1.40APjs = Kx Pe = 0.20 3.00 = 0.60kWQjs = Pjs tg = 0.60 1.17 = 0.70kvA(5)數(shù)控鋼筋調(diào)直切斷機(jī)Kx = 0.2,Cos = 0.65,tg = (1 - Cos2)0.5/ Cos = (1 - 0.652)0.5 / 0.65 = 1.17Pe = n P (e/)0.5 = 1.00 3.00 (0.40 / 0.40)0.5 = 3.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.20 3.00 1000 / (1.732 380 0.65) = 1.40APjs = Kx Pe = 0.20 3.00 = 0.60kWQjs = Pjs tg = 0.60 1.17 = 0.70kvA(6)電動(dòng)切割機(jī)Kx = 0.3,Cos = 0.45,tg = (1 - Cos2)0.5/ Cos = (1 - 0.452)0.5 / 0.45 = 1.98Pe = n P (e/)0.5 = 1.00 1.80 (0.40 / 0.40)0.5 = 1.80kWIj1 = Kx Pe / (1.732 Ue cos) = 0.30 1.80 1000 / (1.732 380 0.45) = 1.82APjs = Kx Pe = 0.30 1.80 = 0.54kWQjs = Pjs tg = 0.54 1.98 = 1.07kvA(7)木工圓鋸Kx = 0.65,Cos = 0.6,tg = (1 - Cos2)0.5/ Cos = (1 - 0.62)0.5 / 0.6 = 1.33Pe = n P (e/)0.5 = 1.00 1.50 (0.40 / 0.40)0.5 = 1.50kWIj1 = Kx Pe / (1.732 Ue cos) = 0.65 1.50 1000 / (1.732 380 0.60) = 2.47APjs = Kx Pe = 0.65 1.50 = 0.98kWQjs = Pjs tg = 0.98 1.33 = 1.30kvA(8)木工平刨床Kx = 0.65,Cos = 0.6,tg = (1 - Cos2)0.5/ Cos = (1 - 0.62)0.5 / 0.6 = 1.33Pe = n P (e/)0.5 = 1.00 3.00 (0.40 / 0.40)0.5 = 3.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.65 3.00 1000 / (1.732 380 0.60) = 4.94APjs = Kx Pe = 0.65 3.00 = 1.95kWQjs = Pjs tg = 1.95 1.33 = 2.60kvA(9)LED泛光燈照明Kx = 0.3,Cos = 0.7,tg = (1 - Cos2)0.5/ Cos = (1 - 0.72)0.5 / 0.7 = 1.02Pe = n P (e/)0.5 = 1.00 0.30 (0.50 / 0.50)0.5 = 0.30kWIj1 = Kx Pe / (1.732 Ue cos) = 0.30 0.30 1000 / (1.732 380 0.70) = 0.20APjs = Kx Pe = 0.30 0.30 = 0.09kWQjs = Pjs tg = 0.09 1.02 = 0.09kvA(10)4-2號(hào)二級(jí)配電箱計(jì)算負(fù)荷用電設(shè)備同期使用系數(shù)Kx=0.70;Ijs = Kx Pe / (1.732 Ue Cos) = 0.70 24.80 1000 / (1.732 380 0.75) = 35.17A;同時(shí)要求分箱用電負(fù)荷不得小于分箱下用電設(shè)備最大計(jì)算負(fù)荷的1.1倍,故:Ijs = max35.17,1.1max(1.03,8.47,1.87,1.40,1.40,1.82,2.47,4.94,0.20,) = 35.17A6、4-3號(hào)二級(jí)配電箱設(shè)備用電負(fù)荷(1)插入式振動(dòng)器Kx = 0.3,Cos = 0.7,tg = (1 - Cos2)0.5/ Cos = (1 - 0.72)0.5 / 0.7 = 1.02Pe = n P (e/)0.5 = 4.00 1.10 (0.40 / 0.40)0.5 = 4.40kWIj1 = Kx Pe / (1.732 Ue cos) = 0.30 4.40 1000 / (1.732 380 0.70) = 2.87APjs = Kx Pe = 0.30 4.40 = 1.32kWQjs = Pjs tg = 1.32 1.02 = 1.35kvA(2)直流電焊機(jī)Kx = 0.3,Cos = 0.6,tg = (1 - Cos2)0.5/ Cos = (1 - 0.62)0.5 / 0.6 = 1.33Pe = n P (e/)0.5 = 4.00 10.00 (0.50 / 1.00)0.5 = 28.28kWIj1 = Kx Pe / (1.732 Ue cos) = 0.30 28.28 1000 / (1.732 380 0.60) = 21.49APjs = Kx Pe = 0.30 28.28 = 8.49kWQjs = Pjs tg = 8.49 1.33 = 11.31kvA(3)沖擊錘鉆Kx = 0.2,Cos = 0.7,tg = (1 - Cos2)0.5/ Cos = (1 - 0.72)0.5 / 0.7 = 1.02Pe = n P (e/)0.5 = 6.00 1.00 (0.40 / 0.40)0.5 = 6.00kWIj1 = Kx Pe / (1.732 Ue cos) = 0.20 6.00 1000 / (1.732 380 0.70) = 2.60APjs = Kx Pe = 0.20 6.00 = 1.20kWQjs = Pjs tg = 1.20 1.02 = 1.22kvA(4)樓層各種照明Kx = 0.3,Cos = 0.7,tg = (1 - Cos2)0.5/ Cos = (1 - 0.72)0.5 / 0.7 =

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