




版權說明:本文檔由用戶提供并上傳,收益歸屬內容提供方,若內容存在侵權,請進行舉報或認領
文檔簡介
CODEVIntroductorySeminar:Day1
“Optics101”
DigitalCameraDesignStudy3280EastFoothillBoulevardPasadena,California91107USA(626)795-9101Fax(626)795-0184e-mail:service@WorldWideWeb:Section1
Optics101
(onaBudget)Goalsand“NotGoals”Goals:BriefoverviewofbasicimagingconceptsIntroducesomelingooflensdesignersProvideresourcesforquickreferenceorfurtherstudyNotGoals:DerivationofequationsExplainallthereistoknowaboutopticaldesignExplainhowCODEVworksSignConventionsDistances:positivetoright
Curvatures:positiveifcenterofcurvatureliestorightofvertex
Angles:positivemeasuredcounterclockwise
Heights:positiveabovetheaxist>0t<0
VCc=1/r<0
VCc=1/r>0q>0q<0LightfromPhysics102Lighttravelsinstraightlines(homogeneousmedia)Snell’sLaw:nsinq
=n’sinq’Paraxialapproximation:Smallangles:sinq~tanq~q;andcosq~1OpticalsurfacesrepresentedbytangentplaneatvertexignoresagincomputingrayheightthicknessisalwayscenterthicknessPowerofasphericalrefractingsurface:
1/f=f
=(n’-n)*cUsefulfortracingraysquicklyanddevelopingaberrationtheoryCardinalPoints6importantpointsalongtheaxisofanopticalsystem2focalpoints(frontandback):
inputlightparalleltotheaxiscrossestheaxisatfocalpointsFandF’2principalpoints(primaryandsecondary):
extendlinesalonginputrayandexitingfocalray;wheretheyintersectdefinesprincipal“planes”whichintersecttheaxisattheprincipalpoints2nodalpoints(firstandsecond):raysaimedatthefirstappeartoemergefromthesecondatthesameangle.“first”pointsdefinedbyparallelraysenteringfromtheright;“second”pointsdefinedbyparallelraysenteringfromtheleftCardinalPointsIllustratedEffectiveFocalLength(EFL)=distancefromprincipalpointtofocalpointP1F1F2EFLEFLApertureStopAperturestop:determineshowmuchlightentersthesystem2specialraysMarginalray:fromon-axisobjectpointthroughtheedgeofthestopChiefray:frommaximumextentofobjectthroughthecenterofthestopApertureStopChiefrayMarginalrayPupilsandtheApertureStopPupilsEntrancepupil:imageofaperturestopviewedfromobjectspaceExitpupil:imageofaperturestopviewedfromimagespaceEntrancepupillocationExitpupillocationEntrancepupildiameter(EPD)ApertureStopSpecifyingtheApertureEPD=EntrancepupildiameterNAO=Numericalapertureinobjectspace(finiteobject)NA=Numericalapertureinimagespacef/#=EFL/EPDNote:someNAOsystemswillnotfillaphysicalaperturestop(commoninphotonicssystems.)Youstillmustspecifyastopsurface.SpecifyingthePupilObjectHH'ImageTHIS0LEntrancepupilEPDqNAO=nsinqq=tan-1(EPD/2L)NA=NAO/RED=n'sinq'FNO=1/(2NA)q'RED=–H'/HInfiniteobject:?/#=EFL/EPDNAOnotvalidSameTriplet,Differentf/#’sf/3f/4f/8“Faster”“Slower”FieldDefinitionFielddefinitiondescribeshowmuchoftheobjectyouimage.Specifyobjectangle,objectheight(finiteobject),imageheight.ObjectImageObjectheight(YOB)Objectangle(YAN)Imageheight(YIM)EntrancepupilLYOB
=-YIM/REDYOB
=-L*tan(YAN)AberrationsPerfectimaging:pointonobjectmapstopointontheimage,forallpointsonobjectandallraysthroughtheaperturestop.Aberrations:deviationsfromthis“1storder”aberrations:Defocus:wrongimagelocationTilt:wrongimageorientationThird-OrderAberrationsSpherical:focallengthfvarieswithapertureheightonlyaberrationon-axisComa:magnificationvarieswithapertureraysthroughedgeofaperturehitimageatdifferentheightthanraysthroughcenterofapertureAstigmatism:sagittal(x-axis)andtangential(y-axis)rayfanshavedifferentfoci.Fieldcurvature:planarobjectformscurvedimagedependsonindexoflensesandtheirpowerDistortion:imagemagnificationdependsonimageheightimageismisshapen,butfocusisn’tchangedRayAberrationCurvesVerticalaxis:distanceonimageplanebetweenchiefrayandcurrentrayHorizontalaxis:relativeheightofrayinaperturestop(orentrance/exitpupil)Chiefrayy(r=1)y(r=-0.75)ImageplaneAperturestopr=1r=-0.75yzRayAberrationCurves(cont.)RelativeAperture
r01-110Rayerror(mm)-0.75y(r=1)y(r=-0.75)Tangential(y-fan)Sagittal(x-fan)RelativeAperture
rRayerror(mm)ChromaticAberrationIndexisfunctionofwavelength:n=n(l)Abbenumberdescribesthedispersion:Vd
=(nd–1)/(nF–nc)
ld=587.6nm(yellow)
lF=486.1nm(blue)
lc=656.3nm(red)SmallVd(Vd~20-50):verydispersive,colorsspreadalotLargeVd(Vd~55-90):lessdispersionRaysandWavesRaysarenormaltowavefrontWavesdiffractataperturesandcaninterfereRayscanimageperfectly;wavescan’tduetodiffractionataperturesApointimagestoAirydiskDiffraction-limitedspotsize(diameter)=2.44l
f/#(microns)2.44
l
f/#IntensityatimageplaneModulationTransferFunction(MTF)Startwithblackandwhitebars(orsinusoid)withspecifiedfrequency.Frequencyin“l(fā)ines/mm”,where“l(fā)ines”=“l(fā)inepairs”(1blackline+1whiteline)=cycleModulation=contrastImax=maximumintensityImin=minimumintensityforobject,contrast=1(pureblackandwhite)MTFMTFSpatialFrequency(cycles/mm)YXTS(R)Object:10IntensityalongimagesliceObject:1010Image1:Image1PositionImage2Image2:MTFdependsontargetorientation:(directionofvariationofintensity)S=Sagittal(a.k.a.R=Radial)orT=TangentialMTF(cont.)Imageisnotperfect;contrastdropsdueto:AberrationDiffractionVignettingVarieswith:fieldpointconsideredorientati
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯(lián)系上傳者。文件的所有權益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網頁內容里面會有圖紙預覽,若沒有圖紙預覽就沒有圖紙。
- 4. 未經權益所有人同意不得將文件中的內容挪作商業(yè)或盈利用途。
- 5. 人人文庫網僅提供信息存儲空間,僅對用戶上傳內容的表現方式做保護處理,對用戶上傳分享的文檔內容本身不做任何修改或編輯,并不能對任何下載內容負責。
- 6. 下載文件中如有侵權或不適當內容,請與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準確性、安全性和完整性, 同時也不承擔用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。
最新文檔
- 安徽省安慶市四中學2025屆八年級英語第二學期期末聯(lián)考試題含答案
- 2025屆浙江省紹興市名校七下英語期中達標檢測模擬試題含答案
- 2025年醫(yī)院信息化升級攻略:電子病歷系統(tǒng)優(yōu)化與醫(yī)療質量提升報告
- 2025年醫(yī)院信息化建設初步設計評估:系統(tǒng)安全與性能分析報告
- 2025年醫(yī)院電子病歷系統(tǒng)優(yōu)化與醫(yī)療信息化投資策略分析報告
- 2025年醫(yī)藥市場醫(yī)藥電商競爭格局:仿制藥一致性評價下的市場競爭力分析報告
- 2025年醫(yī)藥企業(yè)研發(fā)外包(CRO)與臨床試驗質量控制體系構建報告
- 江蘇省蘇州市星港學校2025屆八下英語期中聯(lián)考試題含答案
- 聚焦2025年工業(yè)互聯(lián)網平臺漏洞掃描技術深度解析與應用策略報告
- 安全轉崗培訓試題及答案
- 星載終端抗輻照設計-洞察及研究
- 2025年湖南省中考生物試卷真題(含標準答案)
- 2025年河北省物流產業(yè)集團招聘筆試參考題庫含答案解析
- 2025年衛(wèi)生系統(tǒng)招聘考試(護理學專業(yè)知識)新版真題卷(附詳細解析)
- 吉林省“BEST合作體”2023?2024學年高一下學期期末考試 數學試題(含解析)
- 2025山西航空產業(yè)集團有限公司校園招聘(第一批)43人筆試參考題庫附帶答案詳解
- 2008-2024年江蘇省連云港贛榆區(qū)事業(yè)單位考試《綜合知識與能力素質》真題試卷及答案
- 貴州省貴陽市觀山湖區(qū)2023-2024學年四年級下學期數學期末試卷(含答案)
- 2025年文物保護工程師職業(yè)資格考試試題及答案
- 2025年煤礦從業(yè)人員安全培訓考試題庫
- 機械制圖-形成性任務2-國開(ZJ)-參考資料
評論
0/150
提交評論