計算機圖形學(xué)--實驗環(huán)境的熟悉及像素點的生成.doc

實驗一 實驗環(huán)境的熟悉及像素點的生成班級 08信計（2）班 學(xué)號 20080502085 姓名 王景超 分數(shù)一、實驗?zāi)康暮鸵螅?、了解和使用TurboC提供的基本圖形函數(shù)2、利用TurboC 2.0作為開發(fā)工具進行圖形編程3、在屏幕上生成任意一個像素點.二、實驗內(nèi)容：1.了解和使用TC 2.0的開發(fā)環(huán)境。2.熟悉TC 2.0開發(fā)環(huán)境的基本編輯命令及功能健，學(xué)會常規(guī)操作。3.理解簡單的TC 2.0程序結(jié)構(gòu)，學(xué)習(xí)完整的TC程序開發(fā)過程。4.了解和使用TC 2.0提供的基本圖形函數(shù)，包括像素點的生成。三、實驗結(jié)果分析1.案例二結(jié)果分析（1）該圖案是由直線圖形組成，這些直線的起點和終點均是一個圓的內(nèi)接正n多邊形的頂點程序代碼如下：繪制整個圖案的過程是一個二重循環(huán)，設(shè)各頂點的坐標為xk,yk,k=0,1,n-1,則繪制過程為：#include graphics.h#include math.h#define X 0#define Y 1#define Z 2typedef float point3;int x=0,y=0;void display(point * P,int n,int color)float C34,t,deltat; point point1,point2; int i,j; setcolor(color); for(j=0;j3;j+) Cj0=P0j; Cj1=-3*P0j+3*P1j; Cj2=3*P0j-6*P1j+3*P2j; Cj3=-P0j+3*P1j-3*P2j+P3j; /*Cj0=P0j-3*P1j+3*P2j-P3j; Cj1=-3*P1j-6*P2j+3*P3j; Cj2=3*P2j-3*P3j; Cj3=P3j; */ point1X=P0X;point1Y=P0Y;point1Z=P0Z; deltat=1.0/n; t=0.0; for(i=1;i=n;i+) t+=deltat; point2X=CX0+t*(CX1+t*(CX2+t*CX3); point2Y=CY0+t*(CY1+t*(CY2+t*CY3); point2Z=CZ0+t*(CZ1+t*(CZ2+t*CZ3); line(point10,point11, point20,point21); point1X=point2X;point1Y=point2Y; point1Z=point2Z; void zhongxing(int x,int y,int s) int i; for(i=x-5;i=x+5;i+) putpixel(i,y,s); for(i=y-5;i=y+5;i+) putpixel(x,i,s); void kongdian(point * pot,int color) int i; setcolor(color); for(i=0;i4;i+) circle(potiX,potiY,3); void shuchu(char * s,int color) setcolor(color); outtextxy(0,0,s);void main()int driver=DETECT,mode; int i=0,j,key,s=1;point pot4=100,200,0,200,250,0,300,200,0,400,250,0; char s1=PLEASE CHOOSE THE CONTROL POINT,s2=PLEASE MOVE THE CONTROL POINT,s3=ESC BE PRESSED; registerbgidriver(EGAVGA_driver); initgraph(&driver,&mode,tc);shuchu(s1,14);kongdian(pot,5);display(pot,50,4);zhongxing(potiX,potiY,2);for(;) if(bioskey(1) key=bioskey(0); if(key=0x4d00) if(s=1) if(i!=3) zhongxing(potiX,potiY,0); i+=1; zhongxing(potiX,potiY,2); if(s=-1) display(pot,50,0);kongdian(pot,0);zhongxing(potiX,potiY,0); potiX+=1; display(pot,50,4);kongdian(pot,5);zhongxing(potiX,potiY,2); if(key=0x011b) outtextxy(0,20,s3); break; if(key=0x4b00) if(s=1) if(i!=0) zhongxing(potiX,potiY,0); i-=1; zhongxing(potiX,potiY,2); if(s=-1) display(pot,50,0);kongdian(pot,0);zhongxing(potiX,potiY,0); potiX-=1; display(pot,50,4);kongdian(pot,5);zhongxing(potiX,potiY,2); if(key=0x5000) if(s=-1) display(pot,50,0);kongdian(pot,0);zhongxing(potiX,potiY,0); potiY+=1; display(pot,50,4);kongdian(pot,5);zhongxing(potiX,potiY,2); if(key=0x4800) if(s=-1) display(pot,50,0);kongdian(pot,0);zhongxing(potiX,potiY,0); potiY-=1; display(pot,50,4);kongdian(pot,5);zhongxing(potiX,p