《Java程序設(shè)計(jì)》實(shí)驗(yàn)報(bào)告七.doc

Java程序設(shè)計(jì)實(shí)驗(yàn)報(bào)告學(xué)號(hào) 201405060432班級(jí)14信計(jì)姓名劉帆指導(dǎo)教師金玲玲實(shí)驗(yàn)題目實(shí)驗(yàn)七、類與對(duì)象31、 實(shí)驗(yàn)?zāi)康?. 掌握抽象類的定義及抽象方法；2. 掌握抽象類的繼承特點(diǎn)；3. 掌握接口的定義和實(shí)現(xiàn)，體會(huì)接口的作用；2、 實(shí)驗(yàn)內(nèi)容1. 編寫(xiě)雇員工資支付程序。定義抽象類雇員類Employee類，并提供方法computeSalary()。不同類型的雇員(定義子類)按不同的方式支付工資。 經(jīng)理：每月獲得一份固定的工資； 銷售人員：在基本工資的基礎(chǔ)上加銷售提成； 一般工人：按工作天數(shù)計(jì)算工資； 試用類的繼承及相關(guān)機(jī)制描述上述功能需求并測(cè)試類。2. 程序功能：在程序中聲明一個(gè)自定義接口NL，用來(lái)計(jì)算一個(gè)人年齡。要求：定義接口NL，接口中定義屬性year，取值為2015；定義抽象方法求年齡age()和輸出信息output()；定義類A實(shí)現(xiàn)接口NL，A中定義屬性姓名和出生年份，其方法按需定義。3. 根據(jù)所提供接口的定義，續(xù)寫(xiě)程序，要求體現(xiàn)對(duì)接口的多重繼承。(方法實(shí)現(xiàn)自定義)interface A int x=10; String fun1();interface B int y=5; void fun2();/續(xù)寫(xiě)3、程序清單：（粘貼源程序代碼）1。abstract class Employee String name; public Employee(String name) =name; public String getName() return name;public abstract double computeSalary();class Manager extends Employee double Salary; public Manager(String name,double Salary) super(name); this.Salary=Salary;public double computeSalary() return Salary; class Salaesman extends Employee double baseSalary; int quantity; double univalent;public Salaesman(String name,double baseSalary,int quantity,double commision) super(name); this.baseSalary=baseSalary; this.quantity=quantity; this.univalent=univalent;public double computeSalary() return baseSalary+quantity*univalent;class Worker extends Employee int days; double daySalary;public Worker(String name,int days,double daySalary) super(name); this.days=days; this.daySalary=daySalary;public double computeSalary() return days*daySalary;public class EmployeeTest public static void main(String args) Manager m=new Manager(劉紅,5000); Salaesman s=new Salaesman(張三,2000,20,300); Worker w=new Worker(李梅,30,100); System.out.println(經(jīng)理工資為：+puteSalary(); System.out.println(銷售工資為：+puteSalary(); System.out.println(工人工資為：+puteSalary(); interface A public static int x=10;public abstract String fun1();interface B public static int y=5;public abstract void fun2();public class Test implements A, B public String fun1() return +x;public void fun2() return +y;public static void main(String args) Test t=new Test();System.out.println(t.fun1();System.out.println(t.fun2();2。interface NL int year=2015; int age(); void output();public class A implements NL String name;int birthyear;public void setName(String name) = name;public void setBirthyear(int birthyear) this.birthyear = birthyear;public int age() return year-birthyear;public void output() return +age;3 interface A public static int x=10;public abstract String fun1();interface B public static int y=5;public abstract void fun2();public class Test implements A, B public String fun1() return 接口A的屬性值:+x;public void fun2() return 接口B的屬性值:+x;public static void main(String args) Test t=new Test()