C語(yǔ)言客房管理系統(tǒng)

1、客房管理系統(tǒng)1. 題目與要求：客房管理系統(tǒng)系統(tǒng)包括新用戶登記功能，統(tǒng)計(jì)功能，查詢功能，修改功能。1.1問(wèn)題提出與要求：建立如下結(jié)構(gòu)體：Struct ClientChar Name20;int Sex;int Age;char ID-card ; /*居民身份證*/ int year ;int month;int date; ;Struct HotelInt Room-ID; /*房間號(hào)*/Int Tel;int Price;bool sign; /*標(biāo)記房間是否為空房間*/Struct Client Client-list； /*實(shí)現(xiàn)兩結(jié)構(gòu)體的嵌套*/ RoomNUM 需求分析根據(jù)題目要求，客

2、房信息要用文件存儲(chǔ),提供文件的輸入輸出操作;在程序中需要對(duì)客房具有登記，統(tǒng)計(jì)，查詢和修改的功能;另外還要用鍵盤(pán)式菜單實(shí)現(xiàn)功能選擇.2.功能實(shí)現(xiàn)設(shè)計(jì):2.1總體設(shè)計(jì):下面來(lái)分析一下整個(gè)系統(tǒng)，根據(jù)上面的要求分析，可將這個(gè)系統(tǒng)設(shè)計(jì)為五大模塊（見(jiàn)下圖）：注冊(cè)模塊，統(tǒng)計(jì)模塊，查詢模塊，修改模塊，退出模塊。其主要功能為：注冊(cè)，統(tǒng)計(jì)，查詢，修改功能?？头抗芾硐到y(tǒng) 系統(tǒng)系統(tǒng) 注冊(cè)統(tǒng)計(jì) 查詢修改退出2.2詳細(xì)設(shè)計(jì): 主函數(shù)主函數(shù)一般設(shè)計(jì)得比較簡(jiǎn)潔，提供輸入，功能處理和輸出部分的函數(shù)調(diào)用。其中各功能模塊用菜單方式選擇。流程圖顯示一系列功能選項(xiàng)輸入n，判斷n是否是？根據(jù)n的值調(diào)用各功能模塊函數(shù)結(jié)束開(kāi)始NY程序voi

3、d main() /*主函數(shù)*/ int n,w=1; /*變量n保存選擇菜單數(shù)字,w判斷輸入的數(shù)字是否在功能菜單對(duì)應(yīng)的數(shù)字范圍之內(nèi)*/ struct Hotel *info; while(w)puts("tt C語(yǔ)言課程設(shè)計(jì) 客房管理系統(tǒng) n");puts("tt 072084班 丁超 學(xué)號(hào):20081003552n");puts("tt*n");puts("tt*MENU*n");puts("tt*1 registration*n"); /*注冊(cè)*/ puts("tt*2stati

4、stic*n"); /*統(tǒng)計(jì)*/ puts("tt*3search*n"); /*查詢*/ puts("tt*4modify *n"); /*修改*/ puts("tt*5exit*n"); /*退出*/ puts("tt*n"); puts("tt*n"); printf("Choice your number(1-5):bb"); scanf("%d",&n); if(n<1|n>5) /*對(duì)選擇的數(shù)字作判斷*/ w=1;

5、 getchar(); switch(n) case 1:regi();break; /*注冊(cè)模塊*/ case 2:stat();break; /*統(tǒng)計(jì)模塊*/ case 3:search();break; /*查詢模塊*/ case 4:modify();break; /*修改模塊*/ case5:tuichu();break; /*退出模塊 */ default: break; getchar(); 功能模塊設(shè)計(jì).1 注冊(cè)模塊 單獨(dú)看各數(shù)據(jù)信息，身份證號(hào)碼均是字符型，可采用字符型數(shù)組；用戶在填完個(gè)人信息，即可進(jìn)行房間預(yù)定。流程圖用戶輸入信息i!=o嗎？ 保存調(diào)用函數(shù) 返回開(kāi)始NY返回主菜

6、單程序regi() /*注冊(cè)模塊*/ int i,n; struct Hotel *info; char s10; char a10="have" printf(" people number:n"); scanf("%d",&n); for(i=0;i<n;i+) info=(struct Hotel*)malloc(sizeof(RoomNUM); if(info=0) printf(" memroy used overn"); inputs(" t Room_ID:n",in

7、fo->Room_ID,10); if(!(char*)(info->Room_ID)0) break; inputs(" t have people put have nopeople put nulln",info->person,10); if(strcmp(a,info->person) inputs("t name:n",info->Client_list.Name,20); inputs("t sex:n",info->Client_list.Sex,10); inputs("

8、t age:n",info->Client_list.Age,10); inputs("t Id_card:n",info->Client_list.ID_card,20); inputs("t year:n",info->Client_list.year,10); inputs("t month:n",info->Client_list.month,10); inputs("t date:n",info->Client_list.date,10); inputs("

9、;t Tel:n",info->Tel,10); inputs("t Price:n",info->Price,10); printf("t registration donen"); start=dls_store(info,start); inputs(char *prompt, char *s,int count) char p255; do printf("%s",prompt); scanf("%s",p); if(strlen(p)>count) printf("

10、too long!n "); while(strlen(p)>count); strcpy(s,p); struct Hotel *dls_store(struct Hotel *i,struct Hotel *top) static struct Hotel *last=0; struct Hotel *old,*p; if(last=NULL) i->next=NULL; i->prior=NULL; last=i; return i; p=top; old=NULL; while(p) if(strcmp(p->Room_ID,i->Room_ID

11、)<0) old=p; p=p->next; else if(p->prior) p->prior->next=i; i->next=p; p->prior=i; return top; i->next=p; i->prior=0; p->prior=i; return i; old->next=i; i->next=0; i->prior=old; last=i; return start; 統(tǒng)計(jì)模塊有兩種數(shù)據(jù)進(jìn)行統(tǒng)計(jì)，被占用的房間和未被占用的房間。流程圖統(tǒng)計(jì)對(duì)象 統(tǒng)計(jì)合適房間統(tǒng)計(jì)被占用房間統(tǒng)計(jì)未被

12、占用房間程序stat() /*統(tǒng)計(jì)模塊*/ struct Hotel *info; char a10="null" char b10="have" int c,count=0; printf("t statistic the used Room_ID put 1, the unused Room_ID put 2 n"); scanf("%d",&c); if(c=1) info=start; while(info) if(!strcmp(a,info->person) printf("Ro

13、om_ID %s n",info->Room_ID); count+; info=info->next; printf("t used rooms are%sn",count); /*統(tǒng)計(jì)被占用的房間*/ if(c=2) info=start; while(info) if(!strcmp(b,info->person) printf("t Room_ID %s n",info->Room_ID); count+; info=info->next; printf("t unused rooms are%s

14、n",count); /*統(tǒng)計(jì)未被占用的房間*/ display(struct Hotel *info) printf("tt name:%sn",info->Client_list.Name); printf("tt sex:%sn",info->Client_list.Sex); printf("tt age:%sn",info->Client_list.Age); printf("tt Id_card:%sn",info->Client_list.ID_card); prin

15、tf("tt year:%sn",info->Client_list.year); printf("tt month:%sn",info->Client_list.month); printf("tt date:%sn",info->Client_list.date); printf("tt Tel:%sn",info->Tel); printf("tt Price:%sn",info->Price); printf("n");

16、查詢模塊查詢通?？杉?xì)分為分類查找，此題中分為合適查找，被占用查找，未被占用查找。再與統(tǒng)計(jì)信息進(jìn)行對(duì)應(yīng)，顯示對(duì)應(yīng)數(shù)據(jù)，則用戶即可知道合適房間。程序 search() /*查詢模塊*/ int b; printf(" t search the fixed room put 1n"); printf(" t search the used room put 2n"); printf(" t search the unused room put 3n"); printf(" t back to the main menu put 4

17、n"); do scanf("%d",&b); switch(b) case 1: search1();break; case 2: search2();break; case 3: search3();break; case 4: return; while(b<1|b>4); struct Hotel *find(char *Room_ID) struct Hotel *info; info=start; while(info) if(!strcmp(Room_ID,info->Room_ID) return info; info=i

18、nfo->next; printf(" t can't findn"); return (NULL); search1() char Room_ID10; struct Hotel *info; printf(" t put the Room_ID n"); scanf("%s",Room_ID); getchar(); info=find(Room_ID); if(!info) printf(" t can't findn"); else display(info); search2() s

19、truct Hotel *info; char a10="null" info=start; while(info) if(!strcmp(info->person,a) display(info); printf("n"); info=info->next; search3() struct Hotel *info; char b10="have" info=start; while(info) if(!strcmp(b,info->person) display(info); printf(" n &q

20、uot;); info=info->next; save() register int t,size; struct Hotel *info; char *p; FILE *fp; if(fp=fopen("mlist","wb")=0) printf(" t file can't openn"); exit(0); printf("t savingn"); size=sizeof(RoomNUM); info=start; while(info) p=(char*)info; for(t=0;t&l

21、t;size;+t) putc(*p+,fp); info=info->next; putc(EOF,fp); fclose(fp); printf("t savedn"); .4修改模塊該模塊的功能是顯示用戶要修改的信息。用戶輸入要修改的信息，根據(jù)輸入信息查對(duì)應(yīng)選項(xiàng)，并提示用戶修改該記錄的那部分信息，根據(jù)用戶的選項(xiàng)修改相應(yīng)的信息。流程圖用戶輸入要修改的信息i!=o嗎？ 顯示找到的記錄調(diào)用修改記錄 返回開(kāi)始NY詢問(wèn)用戶是否繼續(xù)修改 提示沒(méi)有找到對(duì)應(yīng)修改信息 NY程序modify() /*修改模塊*/ struct Hotel *info; char Room_ID10

22、; char a10="have" char c10="null" int b,f; printf(" t examine the information 1n"); /*檢驗(yàn)信息*/ printf(" t change the information 2n"); /*修改信息*/ printf(" t back to the main menu 3n"); /*返回主菜單*/ scanf("%d",&b); if(b=1)search(); if(b=2) prin

23、tf(" t put the Room_IDn"); scanf("%s",Room_ID); info=find(Room_ID); if(!info)printf("t can't findn"); else display(info);printf("t Change Entry n"); if(!strcmp(a,info->person) inputs("t put null:n",info->person,10); if(!strcmp(c,info->pe

24、rson) inputs("t name:n",info->Client_list.Name,20); inputs("t sex:n",info->Client_list.Sex,10); inputs("t age:n",info->Client_list.Age,10); inputs("t Id_card:n",info->Client_list.ID_card,20); inputs("t year:n",info->Client_list.year,10

25、); inputs("t month:n",info->Client_list.month,10); inputs("t date:n",info->Client_list.date,10); inputs("t Tel:n",info->Tel,10); inputs("t Price:n",info->Price,10); if(b=3) return; 退出模塊該模塊需要有保存，退出，返回三個(gè)操作。程序顯示一系列功能選項(xiàng)輸入n，判斷n是否是3？根據(jù)n的值調(diào)用各功能模塊函

26、數(shù)結(jié)束開(kāi)始NY程序tuichu() /*退出模塊*/ int d; printf("t suggest you save the message,if save put 1,sure to exit put 2 ,back to main menu put 3n"); scanf("%d",&d); if(d=1) save(); /*保存*/ if(d=2) printf("t Thank you for useing the system!n"); /*退出*/ if(d=3) printf("t backn"); /*返回*/ exit(0); 3. 學(xué)習(xí)心得在老師的帶領(lǐng)下進(jìn)行了C語(yǔ)言程序?qū)嵺`學(xué)習(xí)。在短短一周的實(shí)習(xí)期間使我獲取了不少新知識(shí)也鞏固了許多老知識(shí)。在這之前，我們已經(jīng)對(duì)C語(yǔ)言這門(mén)課程學(xué)習(xí)了一個(gè)學(xué)期，對(duì)其有了一定的了解，但是也僅僅是停留在學(xué)習(xí)了解的范圍，對(duì)