基本路徑測試法和單元測試工具JUnit的使用

1、精選優(yōu)質(zhì)文檔-傾情為你奉上實驗報告實驗序號：02實驗項目名稱：基本路徑測試法和單元測試工具JUnit的使用學號姓名曹鋒專業(yè)、班09軟件工程一班實驗地點1#316指導教師崔建峰實驗時間2012/3/5一、實驗目的l 掌握基本路徑測試方法；l 了解在Eclipse環(huán)境下JUnit單元測試工具的安裝和使用方法；l 針對一個實際問題，在JUnit環(huán)境下設計并執(zhí)行測試用例。二、實驗要求l 開發(fā)環(huán)境：Eclipse v3.7及以上版本；JUnit v4.10及以上版本；文本編輯軟件。 l 硬件要求：CPU PIV 以上，256M 內(nèi)存，1G 硬盤空間。l 系統(tǒng)要求：Windows98/Me/XP/NT/2

2、000，IE 5 以上。三、實驗內(nèi)容與步驟1. 下載并安裝JDK+Eclipse，學習Eclipse安裝與使用方法。2. 下載并安裝JUnit，學習JUnit安裝與使用方法。3. 通讀自動售貨機程序，并將其在Eclipse環(huán)境下運行。問題描述，程序流程圖和程序源代碼見附錄。4. 按照如下格式，采用基本路徑測試法編寫測試用例（要有程序流程控制圖，基本路徑）。編號輸入值Type輸入值money狀態(tài)預輸出實際情況1Beer5C各資源剩余Input Information Type: Beer; Money: 5 Cents; Change: 0Current StateBeer: 5Orange J

3、uice: 65 Cents: 71 Dollar: 6與預期相同2OrangeJuice5C各資源剩余Input Information Type: OrangeJuice; Money: 5 Cents; Change: 0Current StateBeer: 6Orange Juice: 55 Cents: 71 Dollar: 6與預期相同3Beer5C沒有啤酒Filure InformationBeer Shortage與預期相同4OrangeJuice5C沒有橙汁Failure InformationOrangeJuice Shortage與預期不同5Cola5C各資源剩余Fail

4、ure InformationType Error與預期相同6Beer1D沒啤酒Failure InformationBeer Shortage與預期不同7Beer1D各資源剩余Input Information Type: Beer; Money: 1 Dollar; Change:5 CentsCurrent StateBeer: 5Orange Juice: 65 Cents: 51 Dollar: 7與預期不同8OrangeJuice1D各資源剩余Input Information Type: OrangeJuice; Money: 1 Dollar; Change: 5 CentsC

5、urrent StateBeer: 6Orange Juice: 55 Cents:51 Dollar: 7與預期不同9OrangeJuice1D沒有橙汁Failure InformationOrangeJuice Shortage與預期不同10Cola1D各資源剩余Failure InformationType Error與預期相同11Beer1D沒有5角Failure InformationChange Shortage與預期不同12OrangeJuice4C各資源剩余Failure InformationMoney Error與預期相同5. 編寫并執(zhí)行基于JUnit的測試用例。6. 提交

6、測試用例程序和該程序運行結果最終畫面。7. 總結本次試驗，并撰寫實驗報告。程序流程圖如圖一所示：（流程圖可復制粘貼到畫圖查看大圖。）圖一實驗截圖：編寫完測試用例，運行程序，源程序有六個錯誤，如圖二所示：圖二根據(jù)相應錯誤修改代碼后測試通過，如圖三所示：圖三四、分析與討論 通過此次實驗，我初步學會了測試工具Junit的使用方法，發(fā)現(xiàn)使用測試工具可以給程序測試帶來很大的方便，使我們更容易找到程序的錯誤。五、教師評語簽名：日期：成績程序源代碼：修改后的代碼：package first;public class SaleMachine private int countOfBeer, countOfOr

7、angeJuice, countOfFiveCents, countOfOneDollar;private String typeOfGoods = Beer, OrangeJuice;private String resultOfDeal;public SaleMachine()initial();public void initial()countOfBeer = 6;countOfOrangeJuice = 6;countOfFiveCents = 6;countOfOneDollar = 6;public SaleMachine(int fiveCents, int oneDollar

8、, int numOfBeer, int numOfOrange)/便于測試的初始化函數(shù)countOfFiveCents = fiveCents;countOfOneDollar = oneDollar;countOfBeer = numOfBeer;countOfOrangeJuice = numOfOrange;public String currentState()String state = Current Staten + Beer: + countOfBeer + n + Orange Juice: + countOfOrangeJuice + n + 5 Cents: + cou

9、ntOfFiveCents + n + 1 Dollar: + countOfOneDollar;return state;public String operation(String type, String money)/type是用戶選擇的產(chǎn)品，money是用戶投幣種類if(money.equalsIgnoreCase(5C) /如果用戶投入5角錢if(type.equals(typeOfGoods0) /如果用戶選擇啤酒if(countOfBeer0) /如果還有啤酒countOfBeer-;countOfFiveCents+;resultOfDeal = Input Informat

10、ion n + Type: Beer; Money: 5 Cents; Change: 0nn + currentState();return resultOfDeal;elseresultOfDeal = Failure Information n + Beer Shortage;return resultOfDeal;else if (type.equals(typeOfGoods1) /用戶選擇橙汁if(countOfOrangeJuice 0)countOfOrangeJuice-;countOfFiveCents+;resultOfDeal = Input Information n

11、 + Type: OrangeJuice; Money: 5 Cents; Change: 0nn + currentState();return resultOfDeal;elseresultOfDeal = Failure Information n + OrangeJuice Shortage;return resultOfDeal;elseresultOfDeal = Failure Information n + Type Error;return resultOfDeal;else if(money.equalsIgnoreCase(1D) /如果用戶投入一元錢/if(countO

12、fFiveCents0) /如果用戶投入一元錢/if(countOfFiveCents 0) /如果用戶有零錢if(type.equals(typeOfGoods0)&countOfBeer0)/如果用戶選擇啤酒而且還有啤酒countOfBeer-;countOfFiveCents-;countOfOneDollar+;resultOfDeal = Input Information n + Type: Beer; Money: 1 Dollar; Change: 5 Centsnn + currentState();return resultOfDeal;else if (type.equa

13、ls(typeOfGoods1)&countOfOrangeJuice0)/如果用戶選擇橙汁而且還有橙汁countOfOrangeJuice -;countOfFiveCents -;countOfOneDollar +;resultOfDeal = Input Information n + Type: OrangeJuice; Money: 1 Dollar; Change: 5 Centsnn + currentState();return resultOfDeal;elseif(type.equals(typeOfGoods0)&countOfBeer=0)resultOfDeal =

14、 Failure Information n + Beer Shortage;return resultOfDeal;else if(type.equals(typeOfGoods1)&countOfOrangeJuice=0)resultOfDeal = Failure Information n + OrangeJuice Shortage;return resultOfDeal;elseresultOfDeal = Failure Information n + Type Error;return resultOfDeal;elseresultOfDeal = Failure Infor

15、mation n + Change Shortage;return resultOfDeal;/else/resultOfDeal = Failure Information n + Money Error;/return resultOfDeal;/resultOfDeal = Failure Information n + Money Error;return resultOfDeal;測試用例代碼：package first;import junit.framework.TestCase;public class TestSaleMachine extends TestCase publ

16、ic void testOperation1() /售貨機各資源均有剩余，用戶投幣5角，選擇啤酒SaleMachine saleMachine1 = new SaleMachine();String expectedResult = Input Information n +Type: Beer; Money: 5 Cents; Change: 0nn +Current Staten +Beer: 5n +Orange Juice: 6n +5 Cents: 7n +1 Dollar: 6;assertEquals(expectedResult, saleMachine1.operation(

17、Beer, 5C);public void testOperation2()/售貨機沒有啤酒剩余，用戶投幣5角，選擇啤酒SaleMachine saleMachine2 = new SaleMachine(6,6,0,6);String expectedResult = Failure Information n + Beer Shortage;assertEquals(expectedResult,saleMachine2.operation(Beer, 5C);public void testOperation3() /售貨機各資源均有剩余，用戶投幣5角，選擇橙汁SaleMachine s

18、aleMachine3 = new SaleMachine();String expectedResult = Input Information n +Type: OrangeJuice; Money: 5 Cents; Change: 0nn +Current Staten +Beer: 6n +Orange Juice: 5n +5 Cents: 7n +1 Dollar: 6;assertEquals(expectedResult, saleMachine3.operation(OrangeJuice, 5C);public void testOperation4()/售貨機沒有橙汁，

19、用戶投幣5角，選擇橙汁SaleMachine saleMachine4 = new SaleMachine(6,6,6,0);String expectedResult = Failure Information n + OrangeJuice Shortage;assertEquals(expectedResult,saleMachine4.operation(OrangeJuice, 5C);public void testOperation5()/用戶投入5角，選擇非啤酒非橙汁SaleMachine saleMachine5 = new SaleMachine(6,6,6,6);Stri

20、ng expectedResult = Failure Information n + Type Error;assertEquals(expectedResult,saleMachine5.operation(Cola, 5C);public void testOperation6()/售貨機有啤酒且有5角幣，用戶投幣1元，選擇啤酒SaleMachine saleMachine6 = new SaleMachine(6,6,6,6);String expectedResult = Input Information n +Type: Beer; Money: 1 Dollar; Change

21、: 5 Centsnn +Current Staten +Beer: 5n +Orange Juice: 6n +5 Cents: 5n +1 Dollar: 7;assertEquals(expectedResult,saleMachine6.operation(Beer, 1D);public void testOperation7() /售貨機沒有啤酒有5角，用戶投幣1元，選擇啤酒SaleMachine saleMachine7 = new SaleMachine(6,6,0,6);String expectedResult = Failure Information n + Beer

22、Shortage;assertEquals(expectedResult, saleMachine7.operation(Beer, 1D);public void testOperation8()/售貨機有橙汁且有5角幣，用戶投幣1元，選擇橙汁SaleMachine saleMachine8 = new SaleMachine(6,6,6,6);String expectedResult = Input Information n +Type: OrangeJuice; Money: 1 Dollar; Change: 5 Centsnn +Current Staten +Beer: 6n +Orange Juice: 5n +5 Cents: 5n +1 Dollar: 7;assertEquals(expectedResult,saleMachine8.operation(OrangeJuice, 1D);public void testOperation9()/售貨機有5角沒有橙汁，用戶投幣1元，選擇橙汁SaleMachine saleMachine9 = new SaleMachine(6,6,6,0);String expectedResult = Failure Information n + OrangeJu