江蘇省蘇州市六校2022-2023學(xué)年高一上學(xué)期期中聯(lián)考數(shù)學(xué)試題（原卷版）

高一上學(xué)期期中數(shù)學(xué)試題一、單選題(本大題共8題，每題5分，共40分)1.若集合SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.已知全集SKIPIF1<0SKIPIF1<0SKIPIF1<0則圖中陰影部分表示的集合是A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<03.已知SKIPIF1<0，則“SKIPIF1<0”是“SKIPIF1<0”的()A.充分不必要條件 B.必要不充分條件C.充要條件 D.既不充分又不必要條件4.已知集合SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0且SKIPIF1<0，則M的個數(shù)為()A.1 B.3 C.4 D.65.若SKIPIF1<0，則函數(shù)SKIPIF1<0的最大值為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<06.若關(guān)于x的不等式SKIPIF1<0的解集中恰有3個正整數(shù)，則實(shí)數(shù)m的取值范圍為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<07.已知實(shí)數(shù)SKIPIF1<0，SKIPIF1<0滿足SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0的最大值為()A.8 B.9 C.16 D.188.已知正實(shí)數(shù)SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0的最小值是()A.2 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、多選題(本大題共4題，每題5分，共20分)9.已知全集SKIPIF1<0，集合SKIPIF1<0，SKIPIF1<0，則()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0的真子集個數(shù)是710.若不等式SKIPIF1<0與SKIPIF1<0(m，n為實(shí)數(shù))同時成立，則下列不等關(guān)系可能成立的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<011.小王從甲地到乙地往返的速度分別為SKIPIF1<0和SKIPIF1<0，其全程的平均速度為SKIPIF1<0，則()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<012.在整數(shù)集Z中，被6除所得余數(shù)為k的所有整數(shù)組成一個“類”，記為SKIPIF1<0，即SKIPIF1<0，SKIPIF1<0，1，2，3，4，5，則()ASKIPIF1<0B.SKIPIF1<0C.“整數(shù)a，b屬于同一“類”的充要條件是“SKIPIF1<0”D.“整數(shù)a，b滿足SKIPIF1<0”是“SKIPIF1<0”必要不充分條件.三、填空題(本大題共4題，每題5分，共20分)13.命題“SKIPIF1<0，SKIPIF1<0”的否定為______.14.某班共40人，其中20人喜歡籃球運(yùn)動，15人喜歡乒乓球運(yùn)動，8人對這兩項(xiàng)運(yùn)動都不喜歡，則喜歡籃球運(yùn)動但不喜歡乒乓球運(yùn)動的人數(shù)為___________.15.SKIPIF1<0在SKIPIF1<0上有解一個必要不充分條件可以是______.16.實(shí)數(shù)SKIPIF1<0滿足SKIPIF1<0，則當(dāng)SKIPIF1<0______時，SKIPIF1<0的最小值為______.四、解答題(本大題共6題，共70分)17.已知集合SKIPIF1<0，SKIPIF1<0在①SKIPIF1<0；②“SKIPIF1<0“是“SKIPIF1<0”充分不必要條件；③SKIPIF1<0這三個條件中任選一個，補(bǔ)充到本題第(2)問的橫線處，求解下列問題.(1)當(dāng)SKIPIF1<0時，求SKIPIF1<0；(2)若______，求實(shí)數(shù)a的取值范圍.18.已知集合SKIPIF1<0，SKIPIF1<0．(1)當(dāng)SKIPIF1<0時，求SKIPIF1<0；(2)SKIPIF1<0是SKIPIF1<0的必要條件，求SKIPIF1<0的取值范圍．19.已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0.(1)求SKIPIF1<0的最小值；(2)求SKIPIF1<0的最小值．20.某企業(yè)開發(fā)了一種大型電子產(chǎn)品，生產(chǎn)這種產(chǎn)品的年固定成本為2500萬元，每生產(chǎn)x百件，需另投入成本SKIPIF1<0(單位：萬元)，當(dāng)年產(chǎn)量不足30百件時，SKIPIF1<0；當(dāng)年產(chǎn)量不小于30百件時，SKIPIF1<0．若每百件電子產(chǎn)品的售價為500萬元，通過市場分析，該企業(yè)生產(chǎn)的電子產(chǎn)品能全部銷售完．(1)求年利潤y(萬元)關(guān)于年產(chǎn)量x(百件)的函數(shù)關(guān)系式；(2)年產(chǎn)量為多少百件時，該企業(yè)在這一電子產(chǎn)品的生產(chǎn)中獲利最大？21設(shè)函數(shù)SKIPIF1<0(1)若不等式SKIPIF1<0的解集是SKIPIF1<0，求不等式SKIPIF1<0的解集；(2)當(dāng)SKIPIF1<0時，SKIPIF1<0對SKIPIF1<0上恒成立，求實(shí)數(shù)SKIPIF1<0的取值范圍.22.定義：已知集合SKIPIF1<0，SKIPIF1<0