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1、stoichiometry involving molar concentrationby, abby leung & peggy fungblock awhat is stoichiometry?lstoichiometry is the relationships between the amount of reactants used in a chemical reaction and the amount of products produced by the reaction. confused when stoichiometry involves molar conce
2、ntration? molarity?moles?!just remember this!we bake fresh magnificent muffins!5 really easy steps1. write an equation2. balance the equation3. find the mole of the given quantity4. molar ratio 5. molarity- use equation to solve your questionfacts you should knowlstp = 22.4 l/mol lmolar concentratio
3、n = molarityc= n/v -or-molarity =mole/volume (in l)lkeep track of sig figs during your calculations!1. write the equationput reactants on the left side of equation & products on the right side.reactants products2. balance equationmake sure that each element has the same number of atoms on both s
4、ides!3. find mole of given quantityconvert given quantity to # of mol of quantity4. molar ratioluse molar ratio to convert moles of given quantity to wanted quantity*note: coefficients in balanced equation represent molar ratio.5. molarity luse step 4s answer & molar concentration to answer ques
5、tion.lthis step turns mol of a quantity to the answer of the question.lets try it together!a student wants to put 50.0l of hydrogen gas at stp into a plastic bag by reacting excess aluminum metal with 3.00m sodium hydroxide solution according to the reaction. step 1: write out the equationhydrogen g
6、as = h2 (g) since hydrogen is a diatomic moleculeal(s) + naoh(aq) + h2o(l) naalo2(aq) + h2(g)reactantsproductsstep 2: balance the equation2al(s) + 2naoh(aq) + 2h2o(l) 2naalo2(aq) + 3h2(g)step 3: find mole of given quantitylgiven quantity: 50.0l hydrogen gas at stp.lmoles of h2 = 50.0l(1mol/22.4l) =
7、step 4: molar ratiolmoles of given quantity: 2.32 mol of h2 lmoles of wanted quantity: ? mol of naohl1.49 mol naoh (step 4 answer)l3.00m sodium hydroxide (naoh) solution (given)you are done!if i were a mole lyrics*tune: if i were a boy by beyonce knowlesif i were a mole even just for a day id get up
8、 every morning just to do stoichiometry problems i love those questionswith molar concentrationexcept i always had a secret to solving all these tricky ones. if i were a mole i could always understandhow you could solve this questionwith five really ea-s-y stepsremember tha-atmolar concentrationis c
9、 equals n over vits also called molarityand you can use stp to solveif i were a molethe first big step is to write out a proper equation with all the right element symbolsstep two is to-oobalance the equation both sidescause all elements need to have same number of atoms on both sidesif i were a molei could always understandhow you could solve this questionwith 5 very eas-s-y stepsnow lets move on for step three i woulduse stp to change litres to molebecause you need moles for step 4use coefficients formula to getthe
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